United States presidential election in Vermont, 1836

United States presidential election in Vermont, 1836

November 3 - December 7, 1836

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate Francis Granger Richard Mentor Johnson Electoral vote 7 0 Popular vote 35,031 14,037 Percentage 59.93 40.07

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

Elections in Vermont
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The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.

Results

References

State Results of the 1836 U.S. presidential election
Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum
General articles	Election timeline
Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1836 elections	House Senate Gubernatorial