United States presidential election in New Hampshire, 1836

November 3 - December 7, 1836

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

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The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%.

Results

United States presidential election in New Hampshire, 1836^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	18,697	75.01%	7	100.00%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	6,228	24.99%	0	0.00%
Total				24,925	100.00%	7	100.00%

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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