Vermont gubernatorial election, 1869

Vermont gubernatorial election, 1869
Vermont
September 7, 1869 (1869-09-07)

 
Candidate Peter T. Washburn Homer W. Heaton
Party Republican Democratic
Popular vote 31,834 11,455
Percentage 73.5% 26.4%

Governor before election

John B. Page
Republican

Elected Governor

Peter T. Washburn
Republican

The Vermont gubernatorial election of 1869 took place on September 7, 1869. Incumbent Republican John B. Page, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Peter T. Washburn defeated Democratic candidate Homer W. Heaton to succeed him. The 1869 election was the final time the Governor of Vermont was elected for a one-year term, changing to a two-year term at the 1870 election.

Results

Vermont gubernatorial election, 1869[2]
Party Candidate Votes % ±
Republican Peter T. Washburn 31,834 73.5 0.0
Democratic Homer W. Heaton 11,455 26.4 0.0
N/A Other 26 0.1 0.0
Total votes 43,315 100

References

  1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 4 October 2015.
  2. "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 4 October 2015.


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