United States House of Representatives election in Vermont, 1990
United States House of Representatives election in Vermont, At-large district, 1990
|
|
|
|
The 1990 United States House of Representatives election in Vermont was held on Tuesday, November 6, 1990 to elect the U.S. Representative from the state's at-large congressional district. The election coincided with the elections of other federal and state offices.
Republican primary
Democratic primary
Libertarian primary
Libertarian primary results[1]
Party |
Candidate |
Votes |
% |
|
Libertarian |
Write-ins |
127 |
100.00 |
Total votes |
127 |
100.00 |
General election
References
|
---|
|
U.S. Senate | |
---|
|
U.S. House | |
---|
|
State governors | |
---|
|
States generally |
- Alabama
- Alaska
- Arizona
- Arkansas
- California
- Colorado
- Connecticut
- Delaware
- Florida
- Georgia
- Hawaii
- Idaho
- Illinois
- Indiana
- Iowa
- Kansas
- Kentucky
- Louisiana
- Maine
- Maryland
- Massachusetts
- Michigan
- Minnesota
- Mississippi
- Missouri
- Montana
- Nebraska
- Nevada
- New Hampshire
- New Jersey
- New Mexico
- New York
- North Carolina
- North Dakota
- Ohio
- Oklahoma
- Oregon
- Pennsylvania
- Rhode Island
- South Carolina
- South Dakota
- Tennessee
- Texas
- Utah
- Vermont
- Virginia
- Washington
- West Virginia
- Wisconsin
- Wyoming
|
---|