United States presidential election in Alaska, 1996

United States presidential election in Alaska, 1996
Alaska
November 5, 1996
 
Nominee Robert Dole Bill Clinton Ross Perot
Party Republican Democratic Reform
Home state Kansas Arkansas Texas
Running mate Jack Kemp Al Gore Pat Choate
Electoral vote 3 0 0
Popular vote 122,746 80,380 26,333
Percentage 50.8% 33.3% 10.9%

County Results
  Dole—50-60%
President before election

Bill Clinton
Democratic

 Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Alaska took place on November 7, 1996 as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for President and Vice President.

Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.[1] Billionaire businessman Ross Perot (Reform-TX) finished in third with 10.9% of the popular vote .

Results

United States presidential election in Alaska, 1996
Party Candidate Running mate Votes Percentage Electoral votes
Republican Robert Dole Jack Kemp 122,746 50.80% 3
Democratic Bill Clinton (incumbent) Al Gore 80,380 33.27% 0
Reform Ross Perot Patrick Choate 26,333 10.90% 0
Green Party Ralph Nader Winona LaDuke 7,597 3.14% 0
Libertarian Harry Browne Jo Jorgensen 2,276 0.94% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 925 0.38% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 729 0.30% 0
Write-ins 634 0.26% 0
Totals 241,620 100.0% 3

References

  1. ↑ Dave Leip's Atlas of United States Presidential Election Results - 1996 Alaska Results


This article is issued from Wikipedia - version of the 9/1/2013. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.