United States presidential election in Maryland, 1824

United States presidential election in Maryland, 1824

October 26 – December 2, 1824

Nominee Andrew Jackson John Quincy Adams Party Democratic-Republican Democratic-Republican Home state Tennessee Massachusetts Running mate John C. Calhoun John C. Calhoun Electoral vote 7 3 Popular vote 14,523 14,632 Percentage 43.73% 44.05%   Nominee William H. Crawford Henry Clay Party Democratic-Republican Democratic-Republican Home state Georgia Kentucky Running mate Nathaniel Macon Nathan Sanford Electoral vote 1 0 Popular vote 3,364 695 Percentage 10.13% 2.09%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

Elections in Maryland
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Ballot measures 2012 Question 6
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Elections by year State Elections 2006 2010

The 1824 United States presidential election in Maryland took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Although Maryland voted for John Quincy Adams over Andrew Jackson, William H. Crawford and Henry Clay, only three electoral votes were assigned to Adams, while Jackson received seven and Crawford received one. Adams won Maryland by a margin of 0.32%.

Results

References

State Results of the 1824 U.S. presidential election
Candidates	John Quincy Adams Andrew Jackson William H. Crawford Henry Clay
General articles	Election timeline
Local results	Alabama Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1824 elections	House Senate Gubernatorial