United States presidential election in Maine, 1840

United States presidential election in Maine, 1840
Maine
October 30 - December 2, 1844
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 7 0
Popular vote 46,612 46,190
Percentage 50.23 49.77
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Maine took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Maine by a margin of 0.46%.

Results

United States presidential election in Maine, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 46,612 50.23% 10 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 46,190 49.77% 0 0.00%
Total 92,802 100.00% 10 100.00%

References

  1. ↑ "1840 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 23 December 2013.
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