United States Senate election in Wyoming, 1988

United States Senate election in Wyoming, 1988

November 8, 1988

Nominee Malcolm Wallop John P. Vinich Party Republican Democratic Popular vote 91,143 89,821 Percentage 50.37% 49.64%

U.S. Senator before election Malcolm Wallop Republican Elected U.S. Senator Malcolm Wallop Republican

Elections in Wyoming
Federal government Presidential elections 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 Primary elections Democratic caucuses 2008 2016 Republican caucuses 2008 2012 2016 United States Senate elections 1976 1988 1994 1996 2000 2002 2006 2008 2008 (special) 2012 2014 House elections 1992 1994 1996 1998 2000 2002 2004 2006 2008 2010 2012 2014 2016
State government General elections 2014 Gubernatorial elections 2002 2006 2010 2014

The 1988 United States Senate election in Wyoming took place on November 8, 1988. Incumbent Republican U.S. Senator Malcolm Wallop ran for re-election to a fourth term, and was narrowly re-elected, defeating the Democratic candidate John Vinich by a margin of a little over 1,300 votes.^[1]

Major candidates

Democratic

• John P. Vinich, Wyoming State Senator

Republican

• Malcolm Wallop, incumbent U.S. Senator

General election

Despite being a reliably Republican state, Vinich, a Democrat, was able to impressively compete with Wallop. During the campaign, Wallop attacked Vinich as being a tax-and-spend liberal who was beholden to labor and anti-business.^[1] Vinich, in turn, cited his "A" score he got from the National Rifle Association due to his votes in the Wyoming Legislature to counter Wallop's attacks, and possibly attract conservative voters.^[1]

Results

References