Spiceland Township, Henry County, Indiana

Spiceland Township
Township

Location in Henry County
Coordinates: 39°49′12″N 85°27′12″W / 39.82000°N 85.45333°W / 39.82000; -85.45333Coordinates: 39°49′12″N 85°27′12″W / 39.82000°N 85.45333°W / 39.82000; -85.45333
Country United States
State Indiana
County Henry
Government
 • Type Indiana township
Area
 • Total 22.32 sq mi (57.8 km2)
 • Land 22.22 sq mi (57.5 km2)
 • Water 0.09 sq mi (0.2 km2)  0.40%
Elevation 1,040 ft (317 m)
Population (2010)
 • Total 2,279
 • Density 102.5/sq mi (39.6/km2)
GNIS feature ID 0453862

Spiceland Township is one of thirteen townships in Henry County, Indiana, United States. As of the 2010 census, its population was 2,279 and it contained 991 housing units.[1]

Spiceland Township was organized in 1842.[2] It was named from the growth of spice bushes within its borders.[2]

Geography

According to the 2010 census, the township has a total area of 22.32 square miles (57.8 km2), of which 22.22 square miles (57.5 km2) (or 99.55%) is land and 0.09 square miles (0.23 km2) (or 0.40%) is water.[1]

Cities and towns

Unincorporated towns

(This list is based on USGS data and may include former settlements.)

Adjacent townships

Major highways

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.
  2. 1 2 Hazzard, George (1906). Hazzard's History of Henry County, Indiana, 1822-1906. G. Hazzard, author and publisher. p. 964.
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