Oran Township, Fayette County, Iowa

Oran Township
Township

Location in Fayette County
Coordinates: 42°41′05″N 92°01′27″W / 42.68472°N 92.02417°W / 42.68472; -92.02417Coordinates: 42°41′05″N 92°01′27″W / 42.68472°N 92.02417°W / 42.68472; -92.02417
Country  United States
State  Iowa
County Fayette
Area
 • Total 36.66 sq mi (94.94 km2)
 • Land 36.65 sq mi (94.91 km2)
 • Water 0.01 sq mi (0.03 km2)  0.03%
Elevation 1,027 ft (313 m)
Population (2010)
 • Total 760
 • Density 21/sq mi (8.0/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)
ZIP codes 50629, 50662
GNIS feature ID 0468467

Oran Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 760.[1]

Geography

According to the United States Census Bureau, Oran Township covers an area of 36.66 square miles (94.94 square kilometers); of this, 36.65 square miles (94.91 square kilometers, 99.97 percent) is land and 0.01 square miles (0.03 square kilometers, 0.03 percent) is water.

Cities, towns, villages

Unincorporated towns

(This list is based on USGS data and may include former settlements.)

Adjacent townships

Cemeteries

The township contains these four cemeteries: Fairbank, Immaculate Conception, Oran Township and Oran Township.

Major highways

Airports and landing strips

School districts

Political districts

References

  1. ↑ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Oran township, Fayette County, Iowa". U.S. Census Bureau, American Factfinder. Retrieved March 5, 2012.
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