Cottonwood, Apache County, Arizona

This article is about the census-designated place in Apache County, Arizona. For the city in Yavapai County, Arizona, see Cottonwood, Arizona.
Cottonwood, Arizona
Census-designated place
Cottonwood
Coordinates: 36°04′23″N 109°53′32″W / 36.07306°N 109.89222°W / 36.07306; -109.89222Coordinates: 36°04′23″N 109°53′32″W / 36.07306°N 109.89222°W / 36.07306; -109.89222
Country United States
State Arizona
County Apache
Area
 • Total 0.14 sq mi (0.37 km2)
 • Land 0.14 sq mi (0.37 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation 6,069 ft (1,850 m)
Population (2010)
 • Total 226
 • Density 1,578/sq mi (609.4/km2)
Time zone MST (UTC-7)
 • Summer (DST) MDT (UTC-6)
FIPS code 04-16360
GNIS feature ID 0003304

Cottonwood is a census-designated place (CDP) in Apache County, Arizona, United States. The population was 226 at the 2010 census.[1]

Geography

Cottonwood is located at 36°04′23″N 109°53′32″W / 36.07306°N 109.89222°W / 36.07306; -109.89222,[2] about 21 miles (34 km) west of Chinle and 22 miles (35 km) east of Pinon.

According to the United States Census Bureau, the CDP has a total area of 0.14 square miles (0.37 km2), all land.[1]

References

  1. 1 2 "Geographic Identifiers: 2010 Demographic Profile Data (G001): Cottonwood CDP, Arizona". U.S. Census Bureau, American Factfinder. Retrieved April 18, 2013.
  2. ↑ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.


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