2005 Welsh Open (snooker)
Tournament information | |
---|---|
Dates | 17–23 January 2005 |
Venue | Newport Centre |
City | Newport |
Country | Wales |
Organisation(s) | WPBSA |
Format | Ranking event |
Highest break | 146 |
Final | |
Champion | Ronnie O'Sullivan |
Runner-up | Stephen Hendry |
Score | 9–8 |
← 2004 2006 → |
The 2005 Welsh Open was a professional ranking snooker tournament that took place between 17 and 23 January 2005 at the Newport Centre in Newport, Wales.
Ronnie O'Sullivan successfully defended his title by beating Stephen Hendry 9–8.
Main draw
Final
Final: Best of 17 frames Newport Centre, Newport, Wales, 23 January 2005.[1] | ||
Ronnie O'Sullivan (1) England |
9–8 | Stephen Hendry (3) Scotland |
Afternoon: 0–96 (96), 42–74 (67), (62) 69–55, 0–140 (140), (59) 72–65 (57), 72–22, 60–30, 41–70 (69) Evening: 0–93 (93), (102) 122–0, 50–74, 0–71 (57), (75) 106–0, (52) 108–6, (131) 132–0 8–71, (67) 68–0 | ||
131 | Highest break | 140 |
2 | Century breaks | 1 |
7 | 50+ breaks | 7 |
Qualifying
Qualifying for the tournament took place at Pontin's in Prestatyn, Wales between 7 January and 9 January 2005.[2]
Century breaks
Qualifying stage centuries
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Televised stage centuries
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References
- 1 2 "Welsh Open 2005". Snooker.org. Retrieved 3 January 2011.
- 1 2 3 "2005 Welsh Open". Global Snooker Centre. Archived from the original on 22 March 2007.
- ↑ "2005 Welsh Open results". worldsnooker.com. World Professional Billiards and Snooker Association. Archived from the original on 13 February 2005. Retrieved 23 June 2012.
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